(2x^8/y^5)^-3

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Solution for (2x^8/y^5)^-3 equation: 


D( x )

y^5 = 0

(2*x^8)/(y^5) = 0

y^5 = 0

y^5 = 0

y^5 = 0

x naleu017Cy do R

(2*x^8)/(y^5) = 0

(2*x^8)/(y^5) = 0

2*x^8*y^-5 = 0 // : 2*y^-5

x^8 = 0

x = 0

x belongs to the empty set

((2*x^8)/(y^5))^-3 = 0

x belongs to the empty set

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